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### Paper:

TR99-002 | 22nd January 1999 00:00

#### Approximating shortest lattice vectors is not harder than approximating closest lattice vectors.

TR99-002
Authors: Oded Goldreich, Daniele Micciancio, Shmuel Safra and Jean-Pierre Seifert.
Publication: 22nd January 1999 13:07
Keywords:

Abstract:

returns approximate closest vectors in a lattice, one may find in
polynomial-time approximate shortest vectors in a lattice.
The level of approximation is maintained; that is, for any function
$f$, the following holds:
Suppose that the subroutine, on input a lattice ${L}$ and a target
vector $w$ (not necessarily in the lattice), outputs ${v} \in {L}$
such that $\|v - w\| \leq f(n)\cdot\|u - w\|$ for any ${u} \in {L}$.
Then, our algorithm, on input a lattice ${L}$, outputs a nonzero
vector ${v} \in {L}$ such that $\|{v}\| \leq f(n)\cdot\|{u}\|$ for
any nonzero vector ${u} \in {L}$.
The result holds for any norm, and preserves the dimension of the
lattice, i.e., the closest vector oracle is called on lattices of
exactly the same dimension as the original shortest vector problem.

This result establishes the widely believed conjecture by which
the shortest vector problem is not harder than the closest vector
problem.
The proof can be easily adapted to establish an analogous result
for the corresponding computational problems for linear codes.

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